If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-17/2x+3/2=0
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
5x^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{10}=0$
| √3x^2+11x+6√3=0 | | 3x+15=175 | | 3(-2+5=11-4x | | 2x^2-14x=5 | | Y=-0.25x-4.7 | | 36=9+3(4t+1 | | x-40+x/2+x=180 | | 7x+17-12x=38 | | 3.21(4.2x-5.1)=1892 | | 3r/5-6=1 | | 4x+213x+3=90 | | 4x+2•13x+3=90 | | 0y=-6 | | 7x+5/7=12/7 | | 7x+5/7=5 | | z-(-7)=15 | | 3(4x+5=-3 | | -40=x-20 | | n+(-10)=-43 | | 8/9-1/2=v | | 2y=1.5y= | | 15=x+-2 | | x=3x300 | | xx6+19=4xx+61 | | 1/2x+3/2x=6 | | (1/4.8)=(1/x)+(1/(x+4)) | | y+6=-3y=26 | | 1/4.8=1/x+1/x+4 | | 7/4x=7/8 | | 2/3x=3/2x | | 2x^2+(4x)^2=360 | | 7/4x=14/5 |